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Sbd 5204 E Fillable 2008 Form : Customize, Finish and forward

in the following video I will show you.how to answer question 10 of the January.2010 OCR call fall past paper okay let's.take a look at the question straight.away it starts off by asking us to.express 1 over 3 minus X 6 minus X and.partial fractions now I'll show you the.proper a long way and I'll show you a.quick way afterwards you want to write 1.over 3 minus X 6 minus X in the.following form well they're two distinct.linear factors on the bottom so they're.partial fractions are a some number a.over the first distinct factor plus some.number B over the second distinct factor.and these two statements would be.identical to each other.okay multiplying a to make common.denominators on this side I would then.get that 1 over 3 minus X 6 minus X.would be identical to a 6 minus X plus B.3 minus X all divided by 3 minus X 6.minus X so 1 then because the.denominators are the same the numerators.must now be the same so 1 is equivalent.to a 6 minus X plus B 3 minus X ok so.putting in values let's change color pen.let's put in a value let's say X is 3.then I'll get 1 is identical 2 & 6 minus.3 which is 3 3 8.so a is a 1/3 and if I put X is equal to.6 in there.I'll get one is equivalent to this.disappears out 3 minus 6 is minus 3 so I.get minus 3 B so B is minus the third so.therefore Express.in this impartial fractions I would.therefore get a is one-third which I'm.going to rise one on top and three on.bottom so as follows and the other one.is - it's going to be - one on top three.on bottom 6 - X and hence we have our.partial fractions the quick way would be.it because they're two distinct linear.factors I can use what's called the.cover-up method I cover up this one and.I'll substitute in the number that would.make that one zero so I substitute in 3.into the rest 1 over 6 minus 3 which is.1 over 3 would be my number for a so I.know a is 1 over 3 and I do the exact.same for the other one I cover-up that.one and put in the number into the.remaining that would make that 0 so put.6 1 over 3 minus 6 which is 1 over minus.3 so that one must be 1 over minus 3 and.I could just write it straight out like.that on to part two it tells us the.chemical reaction the amount X grams in.the substance is changing with respect.to time in the following differential.equation and it gives us some boundary.conditions it asks us to show the K is a.third learn five over four this constant.K how I'm going to solve this is as.usual separating variables and integrate.I'm going to bring everything with X.onto one side so divide both sides by 3.- X 6 - X and then I'm going to multiply.both sides by DT to get the T on this.side and I'm going to integrate so all.in one move I'm going to do as follows.I'm going to get 1 over 3 minus X 6 - X.DX with an integral must be equal to K.DT and the integral of this now how do i.integrate this on the left hand side.well I can't as it is but I can if I.express it as partial fractions so you.should be thinking back to part 1 this.is actually the integral and we.of 1 over 3 3 minus X minus 1 over 3 6.minus X all with respect to X and this.here is a simple integral this.integrated to K T plus some other.constant of integration which I'll call.C.so let's integrate this side this.integrates simply 2 minus 1/3 learn of 3.minus X and this integrates to this.would integrate 2 minus 1/3 learn 6.minus X book you've already gotten - so.this becomes plus 1/3 learn 6 minus X is.equal to K T plus C I might combine all.these our factorize out 1/3 and I get.lune 6 minus X minus 1 3 minus X which I.can buy to be learn 6 minus X divided by.3 minus X and all of that is equal to KT.plus constant C now I've got some.boundary conditions here T is 0 and X is.0 and T is 1 when X is 1 but I can.substitute in to work out the constant C.and K so let's do that with a different.color pen I know when T is 0 that X is 0.so putting an X is 0 here I just get 1/3.1/2 and putting in T 0 here and this.disappears so I get that is equal to C.so I've worked on my first constant so.therefore I've got 1/3 learn 6 minus x.over 3 minus X is equal to K T plus 1/3.1/2 and then I want to work what I've.got when T is 1 X is 1 so stopping all.that in solving one in here I'd get 1/3.learn 5 over 2 so 5 over 2 is equal to 1.in here will just get me K plus 1/3 the.- and I could subtract 1/3 of them - of.both sides and get the K is equal to 1/3.learn 5 over 2 minus 1/3 learn to sew.then factoring out the third I get 1/3.learn a third of learn 5 over 2 minus.1/2 is equal to K and I can use my.subtract with lunge or lunate a.Columbian on a over B so lune 5 over 2.minus 1/2 is lune 5 over 2 divided by 2.which is 5 over 4 so I get K is a third.learn 5 over 4 which is as required in.the question so moving on to the last.part it once the value of x when T is 2.so let's go back and write out our.answer to the differential equation the.particular solution our answer is then.given by this this formula here so it's.1/3 1/6 minus x over 3 minus X so the.particular solution is 1/3 learn 6 minus.x over 3 minus X is equal to and it's K.T and K is 1/3 1/3 1/5 over 4 so this is.1/3 learn five over four all multiplied.by T and plus R plus the constant of.integration which we had was a third one.two so we get plus a third than two so.that's our particular solution we want.to find X when T is 2 so we substitute.in T is 2 we get 1/3 learn 6 minus x.over 3 minus x must be equal to well.this is 2 so I'm going to have 2/3 then.5 over 4 plus 1/3 1/2 why don't I times.everything by 3 to remove the thirds and.I get learn 6 minus x over 3 minus X.would be equal to 2 learn 5 over 4.Plus learn to and I could bring the.power to up actually might make things.slightly easier I would get learn 5 over.4 squared which is 25 over 16 plus 1/2.and I could combine these loans by.multiplying them so that's lune 50 over.60 that's 2 times 25 over 16 and all of.this is equal to learn 6 minus x over 3.minus X so if two limbs are equal the.number inside the lens must be the same.so 6 over X divided by 3 minus X must be.equal to 50 over 16 multiply both sides.by 16 and multiply both sides by 3 minus.X you get the following 16 6 minus X is.equal to 53 minus X multiplying out 16.times 6 is equal to 96 minus 16 X is.equal to 150 minus 50x add 50 X to both.sides subtract 96 if I added 50 X to.both sides I would get 34 X is equal to.150 minus 96 and I'd get 50 for dividing.both sides by the 34 I would get X is 54.over 30 for 154 over 34 is 27 over 17 so.X is equal to 27 over 17 okay thank you.very much for listening and watching.this video I hope you found it useful in.your revision.

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Sbd 5204 E Fillable 2008 Form FAQs

Notice answers to listed questions about Sbd 5204 E Fillable 2008 Form . Find out the most welcome topics and more.

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How do I create a fillable HTML form online that can be downloaded as a PDF? I have made a framework for problem solving and would like to give people access to an online unfilled form that can be filled out and downloaded filled out.

If it's a single-page form, the unprofessional way to download the filled form as PDF is to print on chrome and firefox browsers and save as PDF or you can implement a simple button that does the same thing or download a section of the page if you don't want a section of the page to be downloaded along with the PDF. On the other hand, the best way to handle this is to use a web-based Form builder like Formplus. Formplus is an online and offline data collection tool that allows you to create and customize your forms to your taste. You or/and respondents can get notifications of the filled form as PDF or docx.

I'm trying to fill out a free fillable tax form. It won't let me click "done with this form" or "efile" which?

It’s can be aggravating! Like Gevin mentioned the “done with this form” button is disabled for form 1040 ONLY. To continue, you have to click the step 2 tab to the right of step 1 . The tab says “E File your tax forms”

How can I make it easier for users to fill out a form on mobile apps?

Make it fast. Ask them as few questions as possible (don't collect unnecessary information) and pre-populate as many fields as possible. Don't ask offputting questions where the respondent might have to enter sensitive personal information. If some users see you collecting sensitive information, they might not be ready to share that with you yet based on what you are offering, and they will think twice about completing the form.

Is there a service that will allow me to create a fillable form on a webpage, and then  email a PDF copy of each form filled out?

Many times while browsing the internet we feel like reading full article,due to many constraints like time, we fail to read so its better get convert the website,article or the facts to PDF file. Usually we use Google Chrome ,for browsing the web.Its most used Web-browser in the world.While you browsing the web using Google Chrome its easy to save the website or article as PDF. Read Full Article on How to convert any web-page as PDF without any software?

How can I fill out Google's intern host matching form to optimize my chances of receiving a match?

I was selected for a summer internship 2016. I tried to be very open while filling the preference form: I choose many products as my favorite products and I said I'm open about the team I want to join. I even was very open in the location and start date to get host matching interviews (I negotiated the start date in the interview until both me and my host were happy.) You could ask your recruiter to review your form (there are very cool and could help you a lot since they have a bigger experience). Do a search on the potential team. Before the interviews, try to find smart question that you are Continue Reading

How do I fill out the form of DU CIC? I couldn't find the link to fill out the form.

Just register on the admission portal and during registration you will get an option for the entrance based course. Just register there. There is no separate form for DU CIC.

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